Base | Representation |
---|---|
bin | 1001101001010110101011… |
… | …00110010111101100000001 |
3 | 2210002212012221212211011101 |
4 | 10310223111212113230001 |
5 | 10240014421310110103 |
6 | 113040415144014401 |
7 | 4316345260003132 |
oct | 464532546275401 |
9 | 83085187784141 |
10 | 21212132113153 |
11 | 6839018640323 |
12 | 2467078161401 |
13 | bab3ac20b807 |
14 | 53495bb53c89 |
15 | 26bb99bdba1d |
hex | 134ad5997b01 |
21212132113153 has 2 divisors, whose sum is σ = 21212132113154. Its totient is φ = 21212132113152.
The previous prime is 21212132113147. The next prime is 21212132113157. The reversal of 21212132113153 is 35131123121212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20090009267344 + 1122122845809 = 4482188^2 + 1059303^2 .
It is a cyclic number.
It is not a de Polignac number, because 21212132113153 - 29 = 21212132112641 is a prime.
It is not a weakly prime, because it can be changed into another prime (21212132113157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606066056576 + 10606066056577.
It is an arithmetic number, because the mean of its divisors is an integer number (10606066056577).
Almost surely, 221212132113153 is an apocalyptic number.
It is an amenable number.
21212132113153 is a deficient number, since it is larger than the sum of its proper divisors (1).
21212132113153 is an equidigital number, since it uses as much as digits as its factorization.
21212132113153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2160, while the sum is 28.
Adding to 21212132113153 its reverse (35131123121212), we get a palindrome (56343255234365).
The spelling of 21212132113153 in words is "twenty-one trillion, two hundred twelve billion, one hundred thirty-two million, one hundred thirteen thousand, one hundred fifty-three".
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