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21212132113153 is a prime number
BaseRepresentation
bin1001101001010110101011…
…00110010111101100000001
32210002212012221212211011101
410310223111212113230001
510240014421310110103
6113040415144014401
74316345260003132
oct464532546275401
983085187784141
1021212132113153
116839018640323
122467078161401
13bab3ac20b807
1453495bb53c89
1526bb99bdba1d
hex134ad5997b01

21212132113153 has 2 divisors, whose sum is σ = 21212132113154. Its totient is φ = 21212132113152.

The previous prime is 21212132113147. The next prime is 21212132113157. The reversal of 21212132113153 is 35131123121212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20090009267344 + 1122122845809 = 4482188^2 + 1059303^2 .

It is a cyclic number.

It is not a de Polignac number, because 21212132113153 - 29 = 21212132112641 is a prime.

It is not a weakly prime, because it can be changed into another prime (21212132113157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606066056576 + 10606066056577.

It is an arithmetic number, because the mean of its divisors is an integer number (10606066056577).

Almost surely, 221212132113153 is an apocalyptic number.

It is an amenable number.

21212132113153 is a deficient number, since it is larger than the sum of its proper divisors (1).

21212132113153 is an equidigital number, since it uses as much as digits as its factorization.

21212132113153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2160, while the sum is 28.

Adding to 21212132113153 its reverse (35131123121212), we get a palindrome (56343255234365).

The spelling of 21212132113153 in words is "twenty-one trillion, two hundred twelve billion, one hundred thirty-two million, one hundred thirteen thousand, one hundred fifty-three".