Base | Representation |
---|---|
bin | 11110110111100111111… |
… | …111010001010110100010 |
3 | 21111210110210220011022222 |
4 | 132313213333101112202 |
5 | 234223421103444340 |
6 | 4302303344431042 |
7 | 306155030663561 |
oct | 36674777212642 |
9 | 7453423804288 |
10 | 2121310999970 |
11 | 748708836658 |
12 | 2a315a918482 |
13 | 125067238466 |
14 | 74959d7bbd8 |
15 | 3a2a80e78b5 |
hex | 1ede7fd15a2 |
2121310999970 has 8 divisors (see below), whose sum is σ = 3818359799964. Its totient is φ = 848524399984.
The previous prime is 2121310999967. The next prime is 2121310999987. The reversal of 2121310999970 is 799990131212.
It can be written as a sum of positive squares in 2 ways, for example, as 1765573905001 + 355737094969 = 1328749^2 + 596437^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106065549989 + ... + 106065550008.
Almost surely, 22121310999970 is an apocalyptic number.
2121310999970 is a deficient number, since it is larger than the sum of its proper divisors (1697048799994).
2121310999970 is a wasteful number, since it uses less digits than its factorization.
2121310999970 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 212131100004.
The product of its (nonzero) digits is 551124, while the sum is 53.
The spelling of 2121310999970 in words is "two trillion, one hundred twenty-one billion, three hundred ten million, nine hundred ninety-nine thousand, nine hundred seventy".
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