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2121316147 = 9349226903
BaseRepresentation
bin111111001110000…
…1011011100110011
312110211122000200201
41332130023130303
513321024104042
6550255100031
7103365614116
oct17634133463
95424560621
102121316147
11999478245
124b2511617
1327a642372
14161a3857d
15c63781b7
hex7e70b733

2121316147 has 4 divisors (see below), whose sum is σ = 2121552400. Its totient is φ = 2121079896.

The previous prime is 2121316103. The next prime is 2121316159. The reversal of 2121316147 is 7416131212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2121316147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2121316247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104103 + ... + 122800.

It is an arithmetic number, because the mean of its divisors is an integer number (530388100).

Almost surely, 22121316147 is an apocalyptic number.

2121316147 is a deficient number, since it is larger than the sum of its proper divisors (236253).

2121316147 is an equidigital number, since it uses as much as digits as its factorization.

2121316147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 236252.

The product of its digits is 2016, while the sum is 28.

The square root of 2121316147 is about 46057.7479584054. The cubic root of 2121316147 is about 1284.8974461298.

Adding to 2121316147 its reverse (7416131212), we get a palindrome (9537447359).

The spelling of 2121316147 in words is "two billion, one hundred twenty-one million, three hundred sixteen thousand, one hundred forty-seven".

Divisors: 1 9349 226903 2121316147