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21213211153 = 88003241051
BaseRepresentation
bin10011110000011001…
…111110101000010001
32000202101101210002011
4103300121332220101
5321421040224103
613424544422521
71350453214441
oct236031765021
960671353064
1021213211153
118aa6339572
124140317a41
132000b46464
141053494121
15842515d6d
hex4f067ea11

21213211153 has 4 divisors (see below), whose sum is σ = 21213540208. Its totient is φ = 21212882100.

The previous prime is 21213211141. The next prime is 21213211157. The reversal of 21213211153 is 35111231212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21213211153 - 213 = 21213202961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21213211157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32523 + ... + 208528.

It is an arithmetic number, because the mean of its divisors is an integer number (5303385052).

Almost surely, 221213211153 is an apocalyptic number.

It is an amenable number.

21213211153 is a deficient number, since it is larger than the sum of its proper divisors (329055).

21213211153 is an equidigital number, since it uses as much as digits as its factorization.

21213211153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 329054.

The product of its digits is 360, while the sum is 22.

Adding to 21213211153 its reverse (35111231212), we get a palindrome (56324442365).

The spelling of 21213211153 in words is "twenty-one billion, two hundred thirteen million, two hundred eleven thousand, one hundred fifty-three".

Divisors: 1 88003 241051 21213211153