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212133000041 = 1912787912557
BaseRepresentation
bin1100010110010000011…
…1001011001101101001
3202021112220122221121022
43011210013023031221
511433422022000131
6241241430222225
721216565514654
oct3054407131551
9667486587538
10212133000041
1181a68603766
1235142ab4975
1317008bacb41
14a3a564089b
1557b871737b
hex31641cb369

212133000041 has 8 divisors (see below), whose sum is σ = 225056148480. Its totient is φ = 199385677008.

The previous prime is 212133000029. The next prime is 212133000067. The reversal of 212133000041 is 140000331212.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 212133000041 - 210 = 212132999017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 212132999983 and 212133000019.

It is not an unprimeable number, because it can be changed into a prime (212133000941) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43953866 + ... + 43958691.

It is an arithmetic number, because the mean of its divisors is an integer number (28132018560).

Almost surely, 2212133000041 is an apocalyptic number.

It is an amenable number.

212133000041 is a deficient number, since it is larger than the sum of its proper divisors (12923148439).

212133000041 is a wasteful number, since it uses less digits than its factorization.

212133000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87912703.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 212133000041 its reverse (140000331212), we get a palindrome (352133331253).

The spelling of 212133000041 in words is "two hundred twelve billion, one hundred thirty-three million, forty-one", and thus it is an aban number.

Divisors: 1 19 127 2413 87912557 1670338583 11164894739 212133000041