Base | Representation |
---|---|
bin | 11110110111101001110… |
… | …010011111011000101011 |
3 | 21111210112220201200111011 |
4 | 132313221302133120223 |
5 | 234224001322012021 |
6 | 4302310344044351 |
7 | 306155545502161 |
oct | 36675162373053 |
9 | 7453486650434 |
10 | 2121341204011 |
11 | 748723896377 |
12 | 2a3168a636b7 |
13 | 125070582283 |
14 | 7495dda1231 |
15 | 3a2aaab1de1 |
hex | 1ede9c9f62b |
2121341204011 has 2 divisors, whose sum is σ = 2121341204012. Its totient is φ = 2121341204010.
The previous prime is 2121341203973. The next prime is 2121341204023. The reversal of 2121341204011 is 1104021431212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2121341204011 is a prime.
It is a super-4 number, since 4×21213412040114 (a number of 50 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (2121341204111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060670602005 + 1060670602006.
It is an arithmetic number, because the mean of its divisors is an integer number (1060670602006).
Almost surely, 22121341204011 is an apocalyptic number.
2121341204011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121341204011 is an equidigital number, since it uses as much as digits as its factorization.
2121341204011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 2121341204011 its reverse (1104021431212), we get a palindrome (3225362635223).
The spelling of 2121341204011 in words is "two trillion, one hundred twenty-one billion, three hundred forty-one million, two hundred four thousand, eleven".
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