Base | Representation |
---|---|
bin | 11110110111101001110… |
… | …010011111011000110111 |
3 | 21111210112220201200111121 |
4 | 132313221302133120313 |
5 | 234224001322012043 |
6 | 4302310344044411 |
7 | 306155545502206 |
oct | 36675162373067 |
9 | 7453486650447 |
10 | 2121341204023 |
11 | 748723896388 |
12 | 2a3168a63707 |
13 | 125070582292 |
14 | 7495dda123d |
15 | 3a2aaab1ded |
hex | 1ede9c9f637 |
2121341204023 has 2 divisors, whose sum is σ = 2121341204024. Its totient is φ = 2121341204022.
The previous prime is 2121341204011. The next prime is 2121341204057. The reversal of 2121341204023 is 3204021431212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2121341204023 - 29 = 2121341203511 is a prime.
It is a super-2 number, since 2×21213412040232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2121341204623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060670602011 + 1060670602012.
It is an arithmetic number, because the mean of its divisors is an integer number (1060670602012).
Almost surely, 22121341204023 is an apocalyptic number.
2121341204023 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121341204023 is an equidigital number, since it uses as much as digits as its factorization.
2121341204023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2121341204023 its reverse (3204021431212), we get a palindrome (5325362635235).
The spelling of 2121341204023 in words is "two trillion, one hundred twenty-one billion, three hundred forty-one million, two hundred four thousand, twenty-three".
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