Base | Representation |
---|---|
bin | 1001101001011001000100… |
… | …01000100011010010110011 |
3 | 2210002222112110000020121110 |
4 | 10310230202020203102303 |
5 | 10240030034013021003 |
6 | 113041150413124403 |
7 | 4316422141034361 |
oct | 464544210432263 |
9 | 83088473006543 |
10 | 21213416142003 |
11 | 683961741a198 |
12 | 2467376189703 |
13 | bab5552440b7 |
14 | 534a404b8631 |
15 | 26bc227c4a03 |
hex | 134b222234b3 |
21213416142003 has 4 divisors (see below), whose sum is σ = 28284554856008. Its totient is φ = 14142277428000.
The previous prime is 21213416141969. The next prime is 21213416142013. The reversal of 21213416142003 is 30024161431212.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 21213416142003 - 210 = 21213416140979 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21213416142013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3535569356998 + ... + 3535569357003.
It is an arithmetic number, because the mean of its divisors is an integer number (7071138714002).
Almost surely, 221213416142003 is an apocalyptic number.
21213416142003 is a deficient number, since it is larger than the sum of its proper divisors (7071138714005).
21213416142003 is an equidigital number, since it uses as much as digits as its factorization.
21213416142003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7071138714004.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 21213416142003 its reverse (30024161431212), we get a palindrome (51237577573215).
The spelling of 21213416142003 in words is "twenty-one trillion, two hundred thirteen billion, four hundred sixteen million, one hundred forty-two thousand, three".
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