Base | Representation |
---|---|
bin | 1100010110010000101… |
… | …1111000010101011001 |
3 | 202021112222222121111111 |
4 | 3011210023320111121 |
5 | 11433422330432213 |
6 | 241241512500321 |
7 | 21216612142603 |
oct | 3054413702531 |
9 | 667488877444 |
10 | 212134233433 |
11 | 81a692763a1 |
12 | 351433aa6a1 |
13 | 17009222365 |
14 | a3a5882173 |
15 | 57b88aca3d |
hex | 31642f8559 |
212134233433 has 2 divisors, whose sum is σ = 212134233434. Its totient is φ = 212134233432.
The previous prime is 212134233401. The next prime is 212134233499. The reversal of 212134233433 is 334332431212.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 189946045584 + 22188187849 = 435828^2 + 148957^2 .
It is a cyclic number.
It is not a de Polignac number, because 212134233433 - 25 = 212134233401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 212134233395 and 212134233404.
It is not a weakly prime, because it can be changed into another prime (212134230433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106067116716 + 106067116717.
It is an arithmetic number, because the mean of its divisors is an integer number (106067116717).
Almost surely, 2212134233433 is an apocalyptic number.
It is an amenable number.
212134233433 is a deficient number, since it is larger than the sum of its proper divisors (1).
212134233433 is an equidigital number, since it uses as much as digits as its factorization.
212134233433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 31104, while the sum is 31.
Adding to 212134233433 its reverse (334332431212), we get a palindrome (546466664645).
The spelling of 212134233433 in words is "two hundred twelve billion, one hundred thirty-four million, two hundred thirty-three thousand, four hundred thirty-three".
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