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21213511586893 is a prime number
BaseRepresentation
bin1001101001011001001111…
…10100101001010001001101
32210002222210002121100101101
410310230213310221101031
510240030232431240033
6113041204102543101
74316424410225353
oct464544764512115
983088702540341
1021213511586893
11683966628a36a
1224673a2137a91
13bab56bc51472
14534a4d0417d3
1526bc2ad7997d
hex134b27d2944d

21213511586893 has 2 divisors, whose sum is σ = 21213511586894. Its totient is φ = 21213511586892.

The previous prime is 21213511586857. The next prime is 21213511586923. The reversal of 21213511586893 is 39868511531212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21154829915844 + 58681671049 = 4599438^2 + 242243^2 .

It is a cyclic number.

It is not a de Polignac number, because 21213511586893 - 229 = 21212974715981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21213511586833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606755793446 + 10606755793447.

It is an arithmetic number, because the mean of its divisors is an integer number (10606755793447).

Almost surely, 221213511586893 is an apocalyptic number.

It is an amenable number.

21213511586893 is a deficient number, since it is larger than the sum of its proper divisors (1).

21213511586893 is an equidigital number, since it uses as much as digits as its factorization.

21213511586893 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3110400, while the sum is 55.

The spelling of 21213511586893 in words is "twenty-one trillion, two hundred thirteen billion, five hundred eleven million, five hundred eighty-six thousand, eight hundred ninety-three".