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21213543344012 = 225303385836003
BaseRepresentation
bin1001101001011001010011…
…01101110010011110001100
32210002222212022100202221222
410310230221231302132030
510240030314044002022
6113041211155342512
74316425244162615
oct464545155623614
983088768322858
1021213543344012
1168396821aaa18
1224673b08b1a38
13bab5756c0166
14534a5334ac0c
1526bc2da4e242
hex134b29b7278c

21213543344012 has 6 divisors (see below), whose sum is σ = 37123700852028. Its totient is φ = 10606771672004.

The previous prime is 21213543344003. The next prime is 21213543344047. The reversal of 21213543344012 is 21044334531212.

It is a super-2 number, since 2×212135433440122 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651692917998 + ... + 2651692918005.

It is an arithmetic number, because the mean of its divisors is an integer number (6187283475338).

Almost surely, 221213543344012 is an apocalyptic number.

It is an amenable number.

21213543344012 is a deficient number, since it is larger than the sum of its proper divisors (15910157508016).

21213543344012 is a wasteful number, since it uses less digits than its factorization.

21213543344012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5303385836007 (or 5303385836005 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 21213543344012 its reverse (21044334531212), we get a palindrome (42257877875224).

The spelling of 21213543344012 in words is "twenty-one trillion, two hundred thirteen billion, five hundred forty-three million, three hundred forty-four thousand, twelve".

Divisors: 1 2 4 5303385836003 10606771672006 21213543344012