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21214036536401 is a prime number
BaseRepresentation
bin1001101001011010001110…
…00111001010110001010001
32210010001010200101112201202
410310231013013022301101
510240032321323131101
6113041332134240545
74316443413224402
oct464550707126121
983101120345652
1021214036536401
116839905637735
122467509ab6155
13bab623930787
14534a9ca4d9a9
1526bc5bec036b
hex134b471cac51

21214036536401 has 2 divisors, whose sum is σ = 21214036536402. Its totient is φ = 21214036536400.

The previous prime is 21214036536349. The next prime is 21214036536403. The reversal of 21214036536401 is 10463563041212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19996986296401 + 1217050240000 = 4471799^2 + 1103200^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21214036536401 is a prime.

Together with 21214036536403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21214036536403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10607018268200 + 10607018268201.

It is an arithmetic number, because the mean of its divisors is an integer number (10607018268201).

Almost surely, 221214036536401 is an apocalyptic number.

It is an amenable number.

21214036536401 is a deficient number, since it is larger than the sum of its proper divisors (1).

21214036536401 is an equidigital number, since it uses as much as digits as its factorization.

21214036536401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 38.

Adding to 21214036536401 its reverse (10463563041212), we get a palindrome (31677599577613).

The spelling of 21214036536401 in words is "twenty-one trillion, two hundred fourteen billion, thirty-six million, five hundred thirty-six thousand, four hundred one".