Base | Representation |
---|---|
bin | 1001101001011010001110… |
… | …10101100111101110101011 |
3 | 2210010001010221112000202112 |
4 | 10310231013111213232223 |
5 | 10240032323310400120 |
6 | 113041332351352535 |
7 | 4316443460354105 |
oct | 464550725475653 |
9 | 83101127460675 |
10 | 21214040325035 |
11 | 6839907795138 |
12 | 246750b22274b |
13 | bab62465907c |
14 | 534a9d358575 |
15 | 26bc5c4bcbc5 |
hex | 134b47567bab |
21214040325035 has 32 divisors (see below), whose sum is σ = 25655937233472. Its totient is φ = 16839173836800.
The previous prime is 21214040324941. The next prime is 21214040325053. The reversal of 21214040325035 is 53052304041212.
It is a de Polignac number, because none of the positive numbers 2k-21214040325035 is a prime.
It is a super-2 number, since 2×212140403250352 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21214040324992 and 21214040325010.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 320988104 + ... + 321054186.
It is an arithmetic number, because the mean of its divisors is an integer number (801748038546).
Almost surely, 221214040325035 is an apocalyptic number.
21214040325035 is a deficient number, since it is larger than the sum of its proper divisors (4441896908437).
21214040325035 is a wasteful number, since it uses less digits than its factorization.
21214040325035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67343.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 21214040325035 its reverse (53052304041212), we get a palindrome (74266344366247).
The spelling of 21214040325035 in words is "twenty-one trillion, two hundred fourteen billion, forty million, three hundred twenty-five thousand, thirty-five".
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