Base | Representation |
---|---|
bin | 1001101001011010001110… |
… | …10101100111101110111101 |
3 | 2210010001010221112000210012 |
4 | 10310231013111213232331 |
5 | 10240032323310400203 |
6 | 113041332351353005 |
7 | 4316443460354132 |
oct | 464550725475675 |
9 | 83101127460705 |
10 | 21214040325053 |
11 | 6839907795154 |
12 | 246750b222765 |
13 | bab624659094 |
14 | 534a9d358589 |
15 | 26bc5c4bcbd8 |
hex | 134b47567bbd |
21214040325053 has 2 divisors, whose sum is σ = 21214040325054. Its totient is φ = 21214040325052.
The previous prime is 21214040324941. The next prime is 21214040325077. The reversal of 21214040325053 is 35052304041212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11109035652484 + 10105004672569 = 3333022^2 + 3178837^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21214040325053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21214040325853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10607020162526 + 10607020162527.
It is an arithmetic number, because the mean of its divisors is an integer number (10607020162527).
Almost surely, 221214040325053 is an apocalyptic number.
It is an amenable number.
21214040325053 is a deficient number, since it is larger than the sum of its proper divisors (1).
21214040325053 is an equidigital number, since it uses as much as digits as its factorization.
21214040325053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 21214040325053 its reverse (35052304041212), we get a palindrome (56266344366265).
The spelling of 21214040325053 in words is "twenty-one trillion, two hundred fourteen billion, forty million, three hundred twenty-five thousand, fifty-three".
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