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21214124413 is a prime number
BaseRepresentation
bin10011110000011101…
…011101100101111101
32000202110010011211121
4103300131131211331
5321421303440123
613425020150541
71350464040136
oct236035354575
960673104747
1021214124413
118aa6902729
124140698451
1320010a6051
141053650c8d
1584264675d
hex4f075d97d

21214124413 has 2 divisors, whose sum is σ = 21214124414. Its totient is φ = 21214124412.

The previous prime is 21214124401. The next prime is 21214124423. The reversal of 21214124413 is 31442141212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14193863044 + 7020261369 = 119138^2 + 83787^2 .

It is a cyclic number.

It is not a de Polignac number, because 21214124413 - 217 = 21213993341 is a prime.

It is a super-2 number, since 2×212141244132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21214124423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10607062206 + 10607062207.

It is an arithmetic number, because the mean of its divisors is an integer number (10607062207).

Almost surely, 221214124413 is an apocalyptic number.

It is an amenable number.

21214124413 is a deficient number, since it is larger than the sum of its proper divisors (1).

21214124413 is an equidigital number, since it uses as much as digits as its factorization.

21214124413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1536, while the sum is 25.

Adding to 21214124413 its reverse (31442141212), we get a palindrome (52656265625).

The spelling of 21214124413 in words is "twenty-one billion, two hundred fourteen million, one hundred twenty-four thousand, four hundred thirteen".