Base | Representation |
---|---|
bin | 1001101001011010100110… |
… | …11001010111111001010111 |
3 | 2210010001200001012110100012 |
4 | 10310231103121113321113 |
5 | 10240033232103312401 |
6 | 113041404415510435 |
7 | 4316451465103103 |
oct | 464552331277127 |
9 | 83101601173305 |
10 | 21214242635351 |
11 | 6839a00a05947 |
12 | 2467566b2841b |
13 | bab657541b0c |
14 | 534abc17c903 |
15 | 26bc701318bb |
hex | 134b53657e57 |
21214242635351 has 2 divisors, whose sum is σ = 21214242635352. Its totient is φ = 21214242635350.
The previous prime is 21214242635221. The next prime is 21214242635407. The reversal of 21214242635351 is 15353624241212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21214242635351 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21214242635299 and 21214242635308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21214242635951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10607121317675 + 10607121317676.
It is an arithmetic number, because the mean of its divisors is an integer number (10607121317676).
Almost surely, 221214242635351 is an apocalyptic number.
21214242635351 is a deficient number, since it is larger than the sum of its proper divisors (1).
21214242635351 is an equidigital number, since it uses as much as digits as its factorization.
21214242635351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 345600, while the sum is 41.
Adding to 21214242635351 its reverse (15353624241212), we get a palindrome (36567866876563).
The spelling of 21214242635351 in words is "twenty-one trillion, two hundred fourteen billion, two hundred forty-two million, six hundred thirty-five thousand, three hundred fifty-one".
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