Base | Representation |
---|---|
bin | 1001101001011010100111… |
… | …11011000001001010011111 |
3 | 2210010001200122210112210212 |
4 | 10310231103323001022133 |
5 | 10240033241333031020 |
6 | 113041405332523035 |
7 | 4316451633055544 |
oct | 464552373011237 |
9 | 83101618715725 |
10 | 21214251455135 |
11 | 6839a0598a322 |
12 | 2467569a8047b |
13 | bab65930c41b |
14 | 534abd3d6bcb |
15 | 26bc70cc4cc5 |
hex | 134b53ec129f |
21214251455135 has 16 divisors (see below), whose sum is σ = 25529484258432. Its totient is φ = 16923195686400.
The previous prime is 21214251455107. The next prime is 21214251455143. The reversal of 21214251455135 is 53155415241212.
It is not a de Polignac number, because 21214251455135 - 26 = 21214251455071 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21214251455092 and 21214251455101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 332855 + ... + 6522215.
It is an arithmetic number, because the mean of its divisors is an integer number (1595592766152).
Almost surely, 221214251455135 is an apocalyptic number.
21214251455135 is a deficient number, since it is larger than the sum of its proper divisors (4315232803297).
21214251455135 is a wasteful number, since it uses less digits than its factorization.
21214251455135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6191314.
The product of its digits is 240000, while the sum is 41.
Adding to 21214251455135 its reverse (53155415241212), we get a palindrome (74369666696347).
The spelling of 21214251455135 in words is "twenty-one trillion, two hundred fourteen billion, two hundred fifty-one million, four hundred fifty-five thousand, one hundred thirty-five".
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