Base | Representation |
---|---|
bin | 1001101001011010101110… |
… | …00000000010110101010101 |
3 | 2210010001211020222121012102 |
4 | 10310231113000002311111 |
5 | 10240033343043314331 |
6 | 113041414415531445 |
7 | 4316453131062404 |
oct | 464552700026525 |
9 | 83101736877172 |
10 | 21214303104341 |
11 | 6839a32057116 |
12 | 2467583229b85 |
13 | bab666c24399 |
14 | 534ac61dd63b |
15 | 26bc755c84cb |
hex | 134b57002d55 |
21214303104341 has 2 divisors, whose sum is σ = 21214303104342. Its totient is φ = 21214303104340.
The previous prime is 21214303104311. The next prime is 21214303104367. The reversal of 21214303104341 is 14340130341212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11447084289316 + 9767218815025 = 3383354^2 + 3125255^2 .
It is a cyclic number.
It is not a de Polignac number, because 21214303104341 - 210 = 21214303103317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21214303104311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10607151552170 + 10607151552171.
It is an arithmetic number, because the mean of its divisors is an integer number (10607151552171).
Almost surely, 221214303104341 is an apocalyptic number.
It is an amenable number.
21214303104341 is a deficient number, since it is larger than the sum of its proper divisors (1).
21214303104341 is an equidigital number, since it uses as much as digits as its factorization.
21214303104341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 21214303104341 its reverse (14340130341212), we get a palindrome (35554433445553).
The spelling of 21214303104341 in words is "twenty-one trillion, two hundred fourteen billion, three hundred three million, one hundred four thousand, three hundred forty-one".
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