Base | Representation |
---|---|
bin | 1100010110010011010… |
… | …1001000101110011011 |
3 | 202021120202100001221121 |
4 | 3011210311020232123 |
5 | 11433433113022400 |
6 | 241242540350111 |
7 | 21220103105413 |
oct | 3054465105633 |
9 | 667522301847 |
10 | 212145048475 |
11 | 81a74392948 |
12 | 35146b45337 |
13 | 1700b53aba9 |
14 | a3a7099643 |
15 | 57b97e721a |
hex | 3164d48b9b |
212145048475 has 12 divisors (see below), whose sum is σ = 269475955560. Its totient is φ = 165576622400.
The previous prime is 212145048461. The next prime is 212145048523. The reversal of 212145048475 is 574840541212.
212145048475 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 212145048475 - 29 = 212145047963 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 103484365 + ... + 103486414.
It is an arithmetic number, because the mean of its divisors is an integer number (22456329630).
Almost surely, 2212145048475 is an apocalyptic number.
212145048475 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
212145048475 is a deficient number, since it is larger than the sum of its proper divisors (57330907085).
212145048475 is a wasteful number, since it uses less digits than its factorization.
212145048475 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 206970830 (or 206970825 counting only the distinct ones).
The product of its (nonzero) digits is 358400, while the sum is 43.
Adding to 212145048475 its reverse (574840541212), we get a palindrome (786985589687).
The spelling of 212145048475 in words is "two hundred twelve billion, one hundred forty-five million, forty-eight thousand, four hundred seventy-five".
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