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2121626426147 is a prime number
BaseRepresentation
bin11110110111111010110…
…010100001101100100011
321111211021210102110200222
4132313322302201230203
5234230042331114042
64302354533233255
7306165611032454
oct36677262415443
97454253373628
102121626426147
1174885a896a48
122a322849282b
131250b76a7877
1474989c0912b
153a2c5b522d2
hex1edfaca1b23

2121626426147 has 2 divisors, whose sum is σ = 2121626426148. Its totient is φ = 2121626426146.

The previous prime is 2121626426107. The next prime is 2121626426159. The reversal of 2121626426147 is 7416246261212.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2121626426147 is a prime.

It is a super-4 number, since 4×21216264261474 (a number of 50 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2121626426098 and 2121626426107.

It is not a weakly prime, because it can be changed into another prime (2121626426107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060813213073 + 1060813213074.

It is an arithmetic number, because the mean of its divisors is an integer number (1060813213074).

Almost surely, 22121626426147 is an apocalyptic number.

2121626426147 is a deficient number, since it is larger than the sum of its proper divisors (1).

2121626426147 is an equidigital number, since it uses as much as digits as its factorization.

2121626426147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 387072, while the sum is 44.

The spelling of 2121626426147 in words is "two trillion, one hundred twenty-one billion, six hundred twenty-six million, four hundred twenty-six thousand, one hundred forty-seven".