Base | Representation |
---|---|
bin | 11110111000010001101… |
… | …111010000000001110101 |
3 | 21111212021121220100222011 |
4 | 132320101233100001311 |
5 | 234231334412141232 |
6 | 4302501045404221 |
7 | 306211264442503 |
oct | 36702157200165 |
9 | 7455247810864 |
10 | 2122011443317 |
11 | 748a38159057 |
12 | 2a3315409671 |
13 | 1251493a158c |
14 | 749c4dcd673 |
15 | 3a2e9856547 |
hex | 1ee11bd0075 |
2122011443317 has 2 divisors, whose sum is σ = 2122011443318. Its totient is φ = 2122011443316.
The previous prime is 2122011443309. The next prime is 2122011443353. The reversal of 2122011443317 is 7133441102212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2119836993156 + 2174450161 = 1455966^2 + 46631^2 .
It is a cyclic number.
It is not a de Polignac number, because 2122011443317 - 23 = 2122011443309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2122011443417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061005721658 + 1061005721659.
It is an arithmetic number, because the mean of its divisors is an integer number (1061005721659).
Almost surely, 22122011443317 is an apocalyptic number.
It is an amenable number.
2122011443317 is a deficient number, since it is larger than the sum of its proper divisors (1).
2122011443317 is an equidigital number, since it uses as much as digits as its factorization.
2122011443317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 2122011443317 its reverse (7133441102212), we get a palindrome (9255452545529).
The spelling of 2122011443317 in words is "two trillion, one hundred twenty-two billion, eleven million, four hundred forty-three thousand, three hundred seventeen".
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