Base | Representation |
---|---|
bin | 1001101001100101100011… |
… | …10001101000101010011011 |
3 | 2210010121211201102101121021 |
4 | 10310302301301220222123 |
5 | 10240132301440133313 |
6 | 113044220010023311 |
7 | 4320050244414655 |
oct | 464626161505233 |
9 | 83117751371537 |
10 | 21220121021083 |
11 | 6841448122076 |
12 | 2468727717b37 |
13 | bac083369c7a |
14 | 5350b8b716d5 |
15 | 26beb624578d |
hex | 134cb1c68a9b |
21220121021083 has 2 divisors, whose sum is σ = 21220121021084. Its totient is φ = 21220121021082.
The previous prime is 21220121021039. The next prime is 21220121021107. The reversal of 21220121021083 is 38012012102212.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21220121021083 - 241 = 19021097765531 is a prime.
It is a super-2 number, since 2×212201210210832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21220121021383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10610060510541 + 10610060510542.
It is an arithmetic number, because the mean of its divisors is an integer number (10610060510542).
Almost surely, 221220121021083 is an apocalyptic number.
21220121021083 is a deficient number, since it is larger than the sum of its proper divisors (1).
21220121021083 is an equidigital number, since it uses as much as digits as its factorization.
21220121021083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 21220121021083 its reverse (38012012102212), we get a palindrome (59232133123295).
The spelling of 21220121021083 in words is "twenty-one trillion, two hundred twenty billion, one hundred twenty-one million, twenty-one thousand, eighty-three".
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