Base | Representation |
---|---|
bin | 1100010110100000101… |
… | …1011101000001100001 |
3 | 202021201200001102002212 |
4 | 3011220023131001201 |
5 | 11434042003333213 |
6 | 241252304451505 |
7 | 21221354461253 |
oct | 3055013350141 |
9 | 667650042085 |
10 | 212201230433 |
11 | 81aa3076215 |
12 | 35161919b95 |
13 | 1701a07c05a |
14 | a3b0721cd3 |
15 | 57be6e39a8 |
hex | 31682dd061 |
212201230433 has 4 divisors (see below), whose sum is σ = 212207227908. Its totient is φ = 212195232960.
The previous prime is 212201230429. The next prime is 212201230481. The reversal of 212201230433 is 334032102212.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 122831323729 + 89369906704 = 350473^2 + 298948^2 .
It is a cyclic number.
It is not a de Polignac number, because 212201230433 - 22 = 212201230429 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 212201230399 and 212201230408.
It is not an unprimeable number, because it can be changed into a prime (212201238433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2945348 + ... + 3016533.
It is an arithmetic number, because the mean of its divisors is an integer number (53051806977).
Almost surely, 2212201230433 is an apocalyptic number.
It is an amenable number.
212201230433 is a deficient number, since it is larger than the sum of its proper divisors (5997475).
212201230433 is an equidigital number, since it uses as much as digits as its factorization.
212201230433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5997474.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 212201230433 its reverse (334032102212), we get a palindrome (546233332645).
The spelling of 212201230433 in words is "two hundred twelve billion, two hundred one million, two hundred thirty thousand, four hundred thirty-three".
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