Base | Representation |
---|---|
bin | 11110111000010010000… |
… | …101000001010001001111 |
3 | 21111212022000122022002221 |
4 | 132320102011001101033 |
5 | 234231342342300111 |
6 | 4302501412000211 |
7 | 306211364111242 |
oct | 36702205012117 |
9 | 7455260568087 |
10 | 2122017150031 |
11 | 748a403a6649 |
12 | 2a3317300067 |
13 | 12514a61bc2c |
14 | 749c5a77259 |
15 | 3a2ea0d2371 |
hex | 1ee1214144f |
2122017150031 has 2 divisors, whose sum is σ = 2122017150032. Its totient is φ = 2122017150030.
The previous prime is 2122017150023. The next prime is 2122017150067. The reversal of 2122017150031 is 1300517102212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2122017150031 - 23 = 2122017150023 is a prime.
It is a super-2 number, since 2×21220171500312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2122017149978 and 2122017150005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2122017157031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061008575015 + 1061008575016.
It is an arithmetic number, because the mean of its divisors is an integer number (1061008575016).
Almost surely, 22122017150031 is an apocalyptic number.
2122017150031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2122017150031 is an equidigital number, since it uses as much as digits as its factorization.
2122017150031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 25.
The spelling of 2122017150031 in words is "two trillion, one hundred twenty-two billion, seventeen million, one hundred fifty thousand, thirty-one".
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