Base | Representation |
---|---|
bin | 11110111000010111000… |
… | …101110000111011000101 |
3 | 21111212111212212001221001 |
4 | 132320113011300323011 |
5 | 234232030403400201 |
6 | 4302514014053301 |
7 | 306213434563162 |
oct | 36702705607305 |
9 | 7455455761831 |
10 | 2122101231301 |
11 | 748a839050a7 |
12 | 2a333b4aa231 |
13 | 125161b7ab6c |
14 | 749d2cc3069 |
15 | 3a302690301 |
hex | 1ee17170ec5 |
2122101231301 has 4 divisors (see below), whose sum is σ = 2122104389152. Its totient is φ = 2122098073452.
The previous prime is 2122101231227. The next prime is 2122101231311. The reversal of 2122101231301 is 1031321012212.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2122101231301 - 215 = 2122101198533 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2122101231311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124065 + ... + 2063878.
It is an arithmetic number, because the mean of its divisors is an integer number (530526097288).
Almost surely, 22122101231301 is an apocalyptic number.
It is an amenable number.
2122101231301 is a deficient number, since it is larger than the sum of its proper divisors (3157851).
2122101231301 is an equidigital number, since it uses as much as digits as its factorization.
2122101231301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3157850.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2122101231301 its reverse (1031321012212), we get a palindrome (3153422243513).
The spelling of 2122101231301 in words is "two trillion, one hundred twenty-two billion, one hundred one million, two hundred thirty-one thousand, three hundred one".
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