Base | Representation |
---|---|
bin | 110000010000000110000011… |
… | …001111011111011010111111 |
3 | 1000211101021212221121021212001 |
4 | 300100012003033133122333 |
5 | 210303341132144113343 |
6 | 2031200542504523131 |
7 | 62461554106155145 |
oct | 6020060317373277 |
9 | 1024337787537761 |
10 | 212212241004223 |
11 | 61687784759a69 |
12 | 1b9741a21804a7 |
13 | 91546b40453a5 |
14 | 3a591ad319595 |
15 | 19801d9e0d44d |
hex | c101833df6bf |
212212241004223 has 2 divisors, whose sum is σ = 212212241004224. Its totient is φ = 212212241004222.
The previous prime is 212212241004157. The next prime is 212212241004227. The reversal of 212212241004223 is 322400142212212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212212241004223 - 217 = 212212240873151 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 212212241004191 and 212212241004200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212212241004227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106106120502111 + 106106120502112.
It is an arithmetic number, because the mean of its divisors is an integer number (106106120502112).
Almost surely, 2212212241004223 is an apocalyptic number.
212212241004223 is a deficient number, since it is larger than the sum of its proper divisors (1).
212212241004223 is an equidigital number, since it uses as much as digits as its factorization.
212212241004223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 212212241004223 its reverse (322400142212212), we get a palindrome (534612383216435).
The spelling of 212212241004223 in words is "two hundred twelve trillion, two hundred twelve billion, two hundred forty-one million, four thousand, two hundred twenty-three".
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