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212220120000041 is a prime number
BaseRepresentation
bin110000010000001101011000…
…110111011110011000101001
31000211102001020001022202012222
4300100031120313132120221
5210304003301210000131
62031204324403043425
762462253260422346
oct6020153067363051
91024361201282188
10212220120000041
116169005819a15a
121b975820970575
13915536b49c4aa
143a597198c57cd
1519804eb9a587b
hexc10358dde629

212220120000041 has 2 divisors, whose sum is σ = 212220120000042. Its totient is φ = 212220120000040.

The previous prime is 212220119999999. The next prime is 212220120000101. The reversal of 212220120000041 is 140000021022212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139218406837225 + 73001713162816 = 11799085^2 + 8544104^2 .

It is a cyclic number.

It is not a de Polignac number, because 212220120000041 - 230 = 212219046258217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 212220119999974 and 212220120000019.

It is not a weakly prime, because it can be changed into another prime (212220120000541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106110060000020 + 106110060000021.

It is an arithmetic number, because the mean of its divisors is an integer number (106110060000021).

Almost surely, 2212220120000041 is an apocalyptic number.

It is an amenable number.

212220120000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

212220120000041 is an equidigital number, since it uses as much as digits as its factorization.

212220120000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 17.

Adding to 212220120000041 its reverse (140000021022212), we get a palindrome (352220141022253).

The spelling of 212220120000041 in words is "two hundred twelve trillion, two hundred twenty billion, one hundred twenty million, forty-one", and thus it is an aban number.