Base | Representation |
---|---|
bin | 11110111000011101100… |
… | …101111111001000111001 |
3 | 21111212210111011102220001 |
4 | 132320131211333020321 |
5 | 234232241321411213 |
6 | 4302532512433001 |
7 | 306216231160420 |
oct | 36703545771071 |
9 | 7455714142801 |
10 | 2122210341433 |
11 | 74902a459166 |
12 | 2a336bb48761 |
13 | 12517b661180 |
14 | 74a035a62b7 |
15 | 3a30c0441dd |
hex | 1ee1d97f239 |
2122210341433 has 8 divisors (see below), whose sum is σ = 2611951189568. Its totient is φ = 1679111478864.
The previous prime is 2122210341403. The next prime is 2122210341439. The reversal of 2122210341433 is 3341430122212.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2122210341433 - 25 = 2122210341401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2122210341439) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11660496291 + ... + 11660496472.
It is an arithmetic number, because the mean of its divisors is an integer number (326493898696).
Almost surely, 22122210341433 is an apocalyptic number.
It is an amenable number.
2122210341433 is a deficient number, since it is larger than the sum of its proper divisors (489740848135).
2122210341433 is a wasteful number, since it uses less digits than its factorization.
2122210341433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23320992783.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 2122210341433 its reverse (3341430122212), we get a palindrome (5463640463645).
The spelling of 2122210341433 in words is "two trillion, one hundred twenty-two billion, two hundred ten million, three hundred forty-one thousand, four hundred thirty-three".
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