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2122213004101 is a prime number
BaseRepresentation
bin11110111000011101110…
…000001001001101000101
321111212210200011201101101
4132320131300021031011
5234232243012112401
64302533045500101
7306216262620331
oct36703560111505
97455720151341
102122213004101
11749030a07713
122a3370a11631
1312517c084108
1474a03a9a7c1
153a30c3bd101
hex1ee1dc09345

2122213004101 has 2 divisors, whose sum is σ = 2122213004102. Its totient is φ = 2122213004100.

The previous prime is 2122213004089. The next prime is 2122213004129. The reversal of 2122213004101 is 1014003122212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1584139407876 + 538073596225 = 1258626^2 + 733535^2 .

It is a cyclic number.

It is not a de Polignac number, because 2122213004101 - 27 = 2122213003973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2122213001101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061106502050 + 1061106502051.

It is an arithmetic number, because the mean of its divisors is an integer number (1061106502051).

Almost surely, 22122213004101 is an apocalyptic number.

It is an amenable number.

2122213004101 is a deficient number, since it is larger than the sum of its proper divisors (1).

2122213004101 is an equidigital number, since it uses as much as digits as its factorization.

2122213004101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 2122213004101 its reverse (1014003122212), we get a palindrome (3136216126313).

The spelling of 2122213004101 in words is "two trillion, one hundred twenty-two billion, two hundred thirteen million, four thousand, one hundred one".