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212221321531 is a prime number
BaseRepresentation
bin1100010110100101100…
…0000110000100111011
3202021210001212010220121
43011221120012010323
511434112124242111
6241254303234111
721222020320012
oct3055130060473
9667701763817
10212221321531
1182003448a2a
12351685a8937
1317021294a8b
14a3b3271a79
1557c1361871
hex316960613b

212221321531 has 2 divisors, whose sum is σ = 212221321532. Its totient is φ = 212221321530.

The previous prime is 212221321469. The next prime is 212221321561. The reversal of 212221321531 is 135123122212.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212221321531 is a prime.

It is a super-2 number, since 2×2122213215312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 212221321496 and 212221321505.

It is not a weakly prime, because it can be changed into another prime (212221321561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106110660765 + 106110660766.

It is an arithmetic number, because the mean of its divisors is an integer number (106110660766).

Almost surely, 2212221321531 is an apocalyptic number.

212221321531 is a deficient number, since it is larger than the sum of its proper divisors (1).

212221321531 is an equidigital number, since it uses as much as digits as its factorization.

212221321531 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 25.

Adding to 212221321531 its reverse (135123122212), we get a palindrome (347344443743).

The spelling of 212221321531 in words is "two hundred twelve billion, two hundred twenty-one million, three hundred twenty-one thousand, five hundred thirty-one".