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212222113153 is a prime number
BaseRepresentation
bin1100010110100101101…
…1000111010110000001
3202021210010100100210221
43011221123013112001
511434112330110103
6241254332223041
721222030124651
oct3055133072601
9667703310727
10212222113153
1182003939766
123516890aa81
13170214b11ab
14a3b33da361
1557c146b1bd
hex31696c7581

212222113153 has 2 divisors, whose sum is σ = 212222113154. Its totient is φ = 212222113152.

The previous prime is 212222113151. The next prime is 212222113219. The reversal of 212222113153 is 351311222212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 192078839824 + 20143273329 = 438268^2 + 141927^2 .

It is a cyclic number.

It is not a de Polignac number, because 212222113153 - 21 = 212222113151 is a prime.

It is a super-2 number, since 2×2122221131532 (a number of 23 digits) contains 22 as substring.

Together with 212222113151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (212222113151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106111056576 + 106111056577.

It is an arithmetic number, because the mean of its divisors is an integer number (106111056577).

Almost surely, 2212222113153 is an apocalyptic number.

It is an amenable number.

212222113153 is a deficient number, since it is larger than the sum of its proper divisors (1).

212222113153 is an equidigital number, since it uses as much as digits as its factorization.

212222113153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1440, while the sum is 25.

Adding to 212222113153 its reverse (351311222212), we get a palindrome (563533335365).

The spelling of 212222113153 in words is "two hundred twelve billion, two hundred twenty-two million, one hundred thirteen thousand, one hundred fifty-three".