Search a number
-
+
2122410433 = 111329694999
BaseRepresentation
bin111111010000001…
…0110100111000001
312110220200121202211
41332200112213001
513321314113213
6550334342121
7103411122343
oct17640264701
95426617684
102122410433
1199a055410
124b295a941
1327a936480
14161c41293
15c64e253d
hex7e8169c1

2122410433 has 16 divisors (see below), whose sum is σ = 2494800000. Its totient is φ = 1780087680.

The previous prime is 2122410427. The next prime is 2122410457. The reversal of 2122410433 is 3340142212.

It is a cyclic number.

It is not a de Polignac number, because 2122410433 - 25 = 2122410401 is a prime.

It is a super-2 number, since 2×21224104332 = 9009252092214494978, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2122410473) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 422068 + ... + 427066.

It is an arithmetic number, because the mean of its divisors is an integer number (155925000).

Almost surely, 22122410433 is an apocalyptic number.

It is an amenable number.

2122410433 is a deficient number, since it is larger than the sum of its proper divisors (372389567).

2122410433 is a wasteful number, since it uses less digits than its factorization.

2122410433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7992.

The product of its (nonzero) digits is 1152, while the sum is 22.

The square root of 2122410433 is about 46069.6259264171. The cubic root of 2122410433 is about 1285.1183472886.

Adding to 2122410433 its reverse (3340142212), we get a palindrome (5462552645).

The spelling of 2122410433 in words is "two billion, one hundred twenty-two million, four hundred ten thousand, four hundred thirty-three".

Divisors: 1 11 13 143 2969 4999 32659 38597 54989 64987 424567 714857 14842031 163262341 192946403 2122410433