Base | Representation |
---|---|
bin | 11110111001011110101… |
… | …110111111001110100011 |
3 | 21111222121122121102121212 |
4 | 132321132232333032203 |
5 | 234242011111021011 |
6 | 4303233152540335 |
7 | 306255301403612 |
oct | 36713656771643 |
9 | 7458548542555 |
10 | 2123303220131 |
11 | 74954034a0a5 |
12 | 2a3615b516ab |
13 | 1252c3bba662 |
14 | 74aa87ad879 |
15 | 3a372e7008b |
hex | 1ee5ebbf3a3 |
2123303220131 has 2 divisors, whose sum is σ = 2123303220132. Its totient is φ = 2123303220130.
The previous prime is 2123303220127. The next prime is 2123303220139. The reversal of 2123303220131 is 1310223033212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2123303220131 - 22 = 2123303220127 is a prime.
It is a super-2 number, since 2×21233032201312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2123303220097 and 2123303220106.
It is not a weakly prime, because it can be changed into another prime (2123303220139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061651610065 + 1061651610066.
It is an arithmetic number, because the mean of its divisors is an integer number (1061651610066).
Almost surely, 22123303220131 is an apocalyptic number.
2123303220131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2123303220131 is an equidigital number, since it uses as much as digits as its factorization.
2123303220131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 2123303220131 its reverse (1310223033212), we get a palindrome (3433526253343).
The spelling of 2123303220131 in words is "two trillion, one hundred twenty-three billion, three hundred three million, two hundred twenty thousand, one hundred thirty-one".
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