Base | Representation |
---|---|
bin | 110000010001110100110001… |
… | …110001101001110100011011 |
3 | 1000211210122202202110022200002 |
4 | 300101310301301221310123 |
5 | 210312313130111443113 |
6 | 2031331324231403215 |
7 | 62503263265130036 |
oct | 6021646161516433 |
9 | 1024718682408602 |
10 | 212331133312283 |
11 | 617231453257a7 |
12 | 1b993242b2350b |
13 | 91629808b792b |
14 | 3a60c4b4c001d |
15 | 1983347a0dc58 |
hex | c11d31c69d1b |
212331133312283 has 2 divisors, whose sum is σ = 212331133312284. Its totient is φ = 212331133312282.
The previous prime is 212331133312279. The next prime is 212331133312339. The reversal of 212331133312283 is 382213331133212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212331133312283 - 22 = 212331133312279 is a prime.
It is not a weakly prime, because it can be changed into another prime (212331133312253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106165566656141 + 106165566656142.
It is an arithmetic number, because the mean of its divisors is an integer number (106165566656142).
Almost surely, 2212331133312283 is an apocalyptic number.
212331133312283 is a deficient number, since it is larger than the sum of its proper divisors (1).
212331133312283 is an equidigital number, since it uses as much as digits as its factorization.
212331133312283 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 93312, while the sum is 38.
Adding to 212331133312283 its reverse (382213331133212), we get a palindrome (594544464445495).
The spelling of 212331133312283 in words is "two hundred twelve trillion, three hundred thirty-one billion, one hundred thirty-three million, three hundred twelve thousand, two hundred eighty-three".
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