Base | Representation |
---|---|
bin | 1001101010000000001101… |
… | …10101111110011101001011 |
3 | 2210011222210011011120010102 |
4 | 10311000012311332131023 |
5 | 10240401104334433141 |
6 | 113054544112040015 |
7 | 4321065022322021 |
oct | 465000665763513 |
9 | 83158704146112 |
10 | 21234433124171 |
11 | 6847521a10a43 |
12 | 246b46083300b |
13 | bb0524523817 |
14 | 535a7588c711 |
15 | 26c55297899b |
hex | 135006d7e74b |
21234433124171 has 2 divisors, whose sum is σ = 21234433124172. Its totient is φ = 21234433124170.
The previous prime is 21234433124161. The next prime is 21234433124237. The reversal of 21234433124171 is 17142133443212.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21234433124171 is a prime.
It is not a weakly prime, because it can be changed into another prime (21234433124141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10617216562085 + 10617216562086.
It is an arithmetic number, because the mean of its divisors is an integer number (10617216562086).
Almost surely, 221234433124171 is an apocalyptic number.
21234433124171 is a deficient number, since it is larger than the sum of its proper divisors (1).
21234433124171 is an equidigital number, since it uses as much as digits as its factorization.
21234433124171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 96768, while the sum is 38.
Adding to 21234433124171 its reverse (17142133443212), we get a palindrome (38376566567383).
The spelling of 21234433124171 in words is "twenty-one trillion, two hundred thirty-four billion, four hundred thirty-three million, one hundred twenty-four thousand, one hundred seventy-one".
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