Base | Representation |
---|---|
bin | 1100010111010011010… |
… | …0111111000011111111 |
3 | 202022021110100222212121 |
4 | 3011310310333003333 |
5 | 11440010320204401 |
6 | 241325325143411 |
7 | 21226542325603 |
oct | 3056464770377 |
9 | 668243328777 |
10 | 212413444351 |
11 | 820a1940719 |
12 | 352009bab67 |
13 | 17052021814 |
14 | a3d09a3503 |
15 | 57d3161ca1 |
hex | 3174d3f0ff |
212413444351 has 2 divisors, whose sum is σ = 212413444352. Its totient is φ = 212413444350.
The previous prime is 212413444301. The next prime is 212413444421. The reversal of 212413444351 is 153444314212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212413444351 - 211 = 212413442303 is a prime.
It is a super-2 number, since 2×2124134443512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212413444301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106206722175 + 106206722176.
It is an arithmetic number, because the mean of its divisors is an integer number (106206722176).
Almost surely, 2212413444351 is an apocalyptic number.
212413444351 is a deficient number, since it is larger than the sum of its proper divisors (1).
212413444351 is an equidigital number, since it uses as much as digits as its factorization.
212413444351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 46080, while the sum is 34.
Adding to 212413444351 its reverse (153444314212), we get a palindrome (365857758563).
The spelling of 212413444351 in words is "two hundred twelve billion, four hundred thirteen million, four hundred forty-four thousand, three hundred fifty-one".
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