Base | Representation |
---|---|
bin | 1100010111010011011… |
… | …1001001100000001001 |
3 | 202022021111102210201110 |
4 | 3011310313021200021 |
5 | 11440010441331101 |
6 | 241325345240533 |
7 | 21226550210034 |
oct | 3056467114011 |
9 | 668244383643 |
10 | 212414011401 |
11 | 820a2198759 |
12 | 35201033149 |
13 | 1705218c957 |
14 | a3d0ab001b |
15 | 57d3224cd6 |
hex | 3174dc9809 |
212414011401 has 4 divisors (see below), whose sum is σ = 283218681872. Its totient is φ = 141609340932.
The previous prime is 212414011367. The next prime is 212414011421. The reversal of 212414011401 is 104110414212.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 212414011401 - 213 = 212414003209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (212414011421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35402335231 + ... + 35402335236.
It is an arithmetic number, because the mean of its divisors is an integer number (70804670468).
Almost surely, 2212414011401 is an apocalyptic number.
It is an amenable number.
212414011401 is a deficient number, since it is larger than the sum of its proper divisors (70804670471).
212414011401 is an equidigital number, since it uses as much as digits as its factorization.
212414011401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70804670470.
The product of its (nonzero) digits is 256, while the sum is 21.
Adding to 212414011401 its reverse (104110414212), we get a palindrome (316524425613).
The spelling of 212414011401 in words is "two hundred twelve billion, four hundred fourteen million, eleven thousand, four hundred one".
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