Base | Representation |
---|---|
bin | 1001101010001110010101… |
… | …00010111011100010001101 |
3 | 2210012201100022002112121221 |
4 | 10311013022202323202031 |
5 | 10241012114411324401 |
6 | 113102240105323341 |
7 | 4321453563016114 |
oct | 465071242734215 |
9 | 83181308075557 |
10 | 21242011433101 |
11 | 684a760748678 |
12 | 2470a16796551 |
13 | bb116159c2a4 |
14 | 536194146c7b |
15 | 26c847e287a1 |
hex | 1351ca8bb88d |
21242011433101 has 2 divisors, whose sum is σ = 21242011433102. Its totient is φ = 21242011433100.
The previous prime is 21242011433081. The next prime is 21242011433129. The reversal of 21242011433101 is 10133411024212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16218702290025 + 5023309143076 = 4027245^2 + 2241274^2 .
It is a cyclic number.
It is not a de Polignac number, because 21242011433101 - 27 = 21242011432973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21242011433501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10621005716550 + 10621005716551.
It is an arithmetic number, because the mean of its divisors is an integer number (10621005716551).
Almost surely, 221242011433101 is an apocalyptic number.
It is an amenable number.
21242011433101 is a deficient number, since it is larger than the sum of its proper divisors (1).
21242011433101 is an equidigital number, since it uses as much as digits as its factorization.
21242011433101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 21242011433101 its reverse (10133411024212), we get a palindrome (31375422457313).
The spelling of 21242011433101 in words is "twenty-one trillion, two hundred forty-two billion, eleven million, four hundred thirty-three thousand, one hundred one".
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