Base | Representation |
---|---|
bin | 11110111010100010001… |
… | …010000110100000010101 |
3 | 21112002112111010101110202 |
4 | 132322202022012200111 |
5 | 234301320201320201 |
6 | 4303541322030245 |
7 | 306325315315112 |
oct | 36724212064025 |
9 | 7462474111422 |
10 | 2124434401301 |
11 | 749a70921273 |
12 | 2a3890948385 |
13 | 125444367b24 |
14 | 74b74b07909 |
15 | 3a3dc414c6b |
hex | 1eea2286815 |
2124434401301 has 2 divisors, whose sum is σ = 2124434401302. Its totient is φ = 2124434401300.
The previous prime is 2124434401291. The next prime is 2124434401307. The reversal of 2124434401301 is 1031044344212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2085788739076 + 38645662225 = 1444226^2 + 196585^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2124434401301 is a prime.
It is a super-2 number, since 2×21244344013012 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2124434401307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1062217200650 + 1062217200651.
It is an arithmetic number, because the mean of its divisors is an integer number (1062217200651).
Almost surely, 22124434401301 is an apocalyptic number.
It is an amenable number.
2124434401301 is a deficient number, since it is larger than the sum of its proper divisors (1).
2124434401301 is an equidigital number, since it uses as much as digits as its factorization.
2124434401301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 2124434401301 its reverse (1031044344212), we get a palindrome (3155478745513).
The spelling of 2124434401301 in words is "two trillion, one hundred twenty-four billion, four hundred thirty-four million, four hundred one thousand, three hundred one".
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