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212503141200 = 24352723613999
BaseRepresentation
bin1100010111101000101…
…1001001101101010000
3202022111201011001211010
43011322023021231100
511440201301004300
6241342251450520
721232011616500
oct3057213115520
9668451131733
10212503141200
1182138535249
1235226a56a40
131706779878c
14a3dc871a00
1557dae7da50
hex317a2c9b50

212503141200 has 180 divisors, whose sum is σ = 791856312000. Its totient is φ = 48572133120.

The previous prime is 212503141183. The next prime is 212503141229. The reversal of 212503141200 is 2141305212.

It is a super-3 number, since 3×2125031412003 (a number of 35 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 1748200 + ... + 1865799.

Almost surely, 2212503141200 is an apocalyptic number.

212503141200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

212503141200 is an abundant number, since it is smaller than the sum of its proper divisors (579353170800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

212503141200 is a wasteful number, since it uses less digits than its factorization.

212503141200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3614034 (or 3614016 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 212503141200 its reverse (2141305212), we get a palindrome (214644446412).

The spelling of 212503141200 in words is "two hundred twelve billion, five hundred three million, one hundred forty-one thousand, two hundred".