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212540412287893 is a prime number
BaseRepresentation
bin110000010100110111101011…
…110001100101101110010101
31000212112122221202202210202211
4300110313223301211232111
5210324230231021203033
62032011414550233421
762524352360101054
oct6024675361455625
91025478852683684
10212540412287893
11617a3978901688
121ba0790a055871
139179623403401
143a6b021a7639b
1519889e58b92cd
hexc14debc65b95

212540412287893 has 2 divisors, whose sum is σ = 212540412287894. Its totient is φ = 212540412287892.

The previous prime is 212540412287881. The next prime is 212540412288007. The reversal of 212540412287893 is 398782214045212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 166090285310404 + 46450126977489 = 12887602^2 + 6815433^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212540412287893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212540412287803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106270206143946 + 106270206143947.

It is an arithmetic number, because the mean of its divisors is an integer number (106270206143947).

Almost surely, 2212540412287893 is an apocalyptic number.

It is an amenable number.

212540412287893 is a deficient number, since it is larger than the sum of its proper divisors (1).

212540412287893 is an equidigital number, since it uses as much as digits as its factorization.

212540412287893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15482880, while the sum is 58.

The spelling of 212540412287893 in words is "two hundred twelve trillion, five hundred forty billion, four hundred twelve million, two hundred eighty-seven thousand, eight hundred ninety-three".