Search a number
-
+
21260553654653 is a prime number
BaseRepresentation
bin1001101010110000110111…
…01111111001000101111101
32210021111012112112222210022
410311120123233321011331
510241313103213422103
6113114544041421525
74323011224215065
oct465303357710575
983244175488708
1021260553654653
116857606305115
12247453049a8a5
13bb2b27c48711
1453703299a3a5
1526d080bda138
hex13561bbf917d

21260553654653 has 2 divisors, whose sum is σ = 21260553654654. Its totient is φ = 21260553654652.

The previous prime is 21260553654631. The next prime is 21260553654661. The reversal of 21260553654653 is 35645635506212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14690831111044 + 6569722543609 = 3832862^2 + 2563147^2 .

It is a cyclic number.

It is not a de Polignac number, because 21260553654653 - 222 = 21260549460349 is a prime.

It is a super-2 number, since 2×212605536546532 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21260553654595 and 21260553654604.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21260553854653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10630276827326 + 10630276827327.

It is an arithmetic number, because the mean of its divisors is an integer number (10630276827327).

Almost surely, 221260553654653 is an apocalyptic number.

It is an amenable number.

21260553654653 is a deficient number, since it is larger than the sum of its proper divisors (1).

21260553654653 is an equidigital number, since it uses as much as digits as its factorization.

21260553654653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440000, while the sum is 53.

The spelling of 21260553654653 in words is "twenty-one trillion, two hundred sixty billion, five hundred fifty-three million, six hundred fifty-four thousand, six hundred fifty-three".