Base | Representation |
---|---|
bin | 11110111100111000001… |
… | …000001101010110111011 |
3 | 21112100000211120210211212 |
4 | 132330320020031112323 |
5 | 234321443311044413 |
6 | 4305035122313335 |
7 | 306444546562253 |
oct | 36747010152673 |
9 | 7470024523755 |
10 | 2126950487483 |
11 | 750042112038 |
12 | 2a42734b884b |
13 | 12575570a113 |
14 | 74d32d44963 |
15 | 3a4d826bca8 |
hex | 1ef3820d5bb |
2126950487483 has 2 divisors, whose sum is σ = 2126950487484. Its totient is φ = 2126950487482.
The previous prime is 2126950487393. The next prime is 2126950487489. The reversal of 2126950487483 is 3847840596212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2126950487483 - 28 = 2126950487227 is a prime.
It is not a weakly prime, because it can be changed into another prime (2126950487489) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1063475243741 + 1063475243742.
It is an arithmetic number, because the mean of its divisors is an integer number (1063475243742).
It is a 1-persistent number, because it is pandigital, but 2⋅2126950487483 = 4253900974966 is not.
Almost surely, 22126950487483 is an apocalyptic number.
2126950487483 is a deficient number, since it is larger than the sum of its proper divisors (1).
2126950487483 is an equidigital number, since it uses as much as digits as its factorization.
2126950487483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23224320, while the sum is 59.
The spelling of 2126950487483 in words is "two trillion, one hundred twenty-six billion, nine hundred fifty million, four hundred eighty-seven thousand, four hundred eighty-three".
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