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212860433 is a prime number
BaseRepresentation
bin11001010111111…
…11111000010001
3112211112102121202
430223333320101
5413443013213
633042200545
75163166232
oct1453777021
9484472552
10212860433
11aa177215
125b353155
133513ab26
14203ad089
1513a49b58
hexcaffe11

212860433 has 2 divisors, whose sum is σ = 212860434. Its totient is φ = 212860432.

The previous prime is 212860399. The next prime is 212860441. The reversal of 212860433 is 334068212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134838544 + 78021889 = 11612^2 + 8833^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212860433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 212860396 and 212860405.

It is not a weakly prime, because it can be changed into another prime (212860463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106430216 + 106430217.

It is an arithmetic number, because the mean of its divisors is an integer number (106430217).

Almost surely, 2212860433 is an apocalyptic number.

It is an amenable number.

212860433 is a deficient number, since it is larger than the sum of its proper divisors (1).

212860433 is an equidigital number, since it uses as much as digits as its factorization.

212860433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

The square root of 212860433 is about 14589.7372491762. The cubic root of 212860433 is about 597.0787941944.

The spelling of 212860433 in words is "two hundred twelve million, eight hundred sixty thousand, four hundred thirty-three".