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213000000232011 = 371000000077337
BaseRepresentation
bin110000011011100011101101…
…010110011101101001001011
31000221011121020020120101002220
4300123203231112131221023
5210404243000024411021
62033002503235025123
762602512366133506
oct6033435526355113
91027147206511086
10213000000232011
116196087a261393
121ba809b113b1a3
1391b0a76cc8a85
143a8537daaa13d
15199594376ecc6
hexc1b8ed59da4b

213000000232011 has 4 divisors (see below), whose sum is σ = 284000000309352. Its totient is φ = 142000000154672.

The previous prime is 213000000231979. The next prime is 213000000232031. The reversal of 213000000232011 is 110232000000312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 213000000232011 - 25 = 213000000231979 is a prime.

It is not an unprimeable number, because it can be changed into a prime (213000000232031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35500000038666 + ... + 35500000038671.

It is an arithmetic number, because the mean of its divisors is an integer number (71000000077338).

Almost surely, 2213000000232011 is an apocalyptic number.

213000000232011 is a deficient number, since it is larger than the sum of its proper divisors (71000000077341).

213000000232011 is an equidigital number, since it uses as much as digits as its factorization.

213000000232011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71000000077340.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 213000000232011 its reverse (110232000000312), we get a palindrome (323232000232323).

The spelling of 213000000232011 in words is "two hundred thirteen trillion, two hundred thirty-two thousand, eleven".

Divisors: 1 3 71000000077337 213000000232011