Base | Representation |
---|---|
bin | 11110111111101101111… |
… | …010000100111110001111 |
3 | 21112121220101020002220121 |
4 | 132333231322010332033 |
5 | 234344220030031211 |
6 | 4310301505125411 |
7 | 306613251165514 |
oct | 36775572047617 |
9 | 7477811202817 |
10 | 2130000236431 |
11 | 751367671611 |
12 | 2a4984929867 |
13 | 125b204bc6b2 |
14 | 75141dbb30b |
15 | 3a615d8b271 |
hex | 1efede84f8f |
2130000236431 has 2 divisors, whose sum is σ = 2130000236432. Its totient is φ = 2130000236430.
The previous prime is 2130000236407. The next prime is 2130000236437. The reversal of 2130000236431 is 1346320000312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2130000236431 - 29 = 2130000235919 is a prime.
It is a super-2 number, since 2×21300002364312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2130000236396 and 2130000236405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2130000236437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065000118215 + 1065000118216.
It is an arithmetic number, because the mean of its divisors is an integer number (1065000118216).
Almost surely, 22130000236431 is an apocalyptic number.
2130000236431 is a deficient number, since it is larger than the sum of its proper divisors (1).
2130000236431 is an equidigital number, since it uses as much as digits as its factorization.
2130000236431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 2130000236431 its reverse (1346320000312), we get a palindrome (3476320236743).
The spelling of 2130000236431 in words is "two trillion, one hundred thirty billion, two hundred thirty-six thousand, four hundred thirty-one".
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