Base | Representation |
---|---|
bin | 110000011011100100101110… |
… | …111011000000100011000011 |
3 | 1000221011201001220121012111102 |
4 | 300123210232323000203003 |
5 | 210404302223141044303 |
6 | 2033003204334005015 |
7 | 62602551554622002 |
oct | 6033445673004303 |
9 | 1027151056535442 |
10 | 213001100331203 |
11 | 61961294234178 |
12 | 1ba8105964676b |
13 | 91b0bc0bb2942 |
14 | 3a85445c32c39 |
15 | 19959aa125288 |
hex | c1b92eec08c3 |
213001100331203 has 4 divisors (see below), whose sum is σ = 213002048419680. Its totient is φ = 213000152242728.
The previous prime is 213001100331121. The next prime is 213001100331251. The reversal of 213001100331203 is 302133001100312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 213001100331203 - 212 = 213001100327107 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (213001100331293) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 473707163 + ... + 474156596.
It is an arithmetic number, because the mean of its divisors is an integer number (53250512104920).
Almost surely, 2213001100331203 is an apocalyptic number.
213001100331203 is a deficient number, since it is larger than the sum of its proper divisors (948088477).
213001100331203 is an equidigital number, since it uses as much as digits as its factorization.
213001100331203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 948088476.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 213001100331203 its reverse (302133001100312), we get a palindrome (515134101431515).
The spelling of 213001100331203 in words is "two hundred thirteen trillion, one billion, one hundred million, three hundred thirty-one thousand, two hundred three".
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