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2130023034131 is a prime number
BaseRepresentation
bin11110111111101111010…
…001000010110100010011
321112121221222010100110212
4132333233101002310103
5234344241344043011
64310304041514335
7306613646026226
oct36775721026423
97477858110425
102130023034131
11751379522893
122a49904a29ab
13125b25142365
14751450335bd
153a617d9108b
hex1efef442d13

2130023034131 has 2 divisors, whose sum is σ = 2130023034132. Its totient is φ = 2130023034130.

The previous prime is 2130023034109. The next prime is 2130023034179. The reversal of 2130023034131 is 1314303200312.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2130023034131 - 222 = 2130018839827 is a prime.

It is a super-2 number, since 2×21300230341312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2130023034097 and 2130023034106.

It is not a weakly prime, because it can be changed into another prime (2130023030131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065011517065 + 1065011517066.

It is an arithmetic number, because the mean of its divisors is an integer number (1065011517066).

Almost surely, 22130023034131 is an apocalyptic number.

2130023034131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2130023034131 is an equidigital number, since it uses as much as digits as its factorization.

2130023034131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 2130023034131 its reverse (1314303200312), we get a palindrome (3444326234443).

The spelling of 2130023034131 in words is "two trillion, one hundred thirty billion, twenty-three million, thirty-four thousand, one hundred thirty-one".