Base | Representation |
---|---|
bin | 11110111111101111110… |
… | …000001111000111111011 |
3 | 21112121222112111210000222 |
4 | 132333233300033013323 |
5 | 234344300442223003 |
6 | 4310304533050255 |
7 | 306614105363423 |
oct | 36775760170773 |
9 | 7477875453028 |
10 | 2130031211003 |
11 | 7513830a8233 |
12 | 2a499318698b |
13 | 125b26a46147 |
14 | 75146161483 |
15 | 3a618958c38 |
hex | 1efefc0f1fb |
2130031211003 has 4 divisors (see below), whose sum is σ = 2130615906168. Its totient is φ = 2129446515840.
The previous prime is 2130031210969. The next prime is 2130031211029. The reversal of 2130031211003 is 3001121300312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2130031211003 - 222 = 2130027016699 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2130031211053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 292342118 + ... + 292349403.
It is an arithmetic number, because the mean of its divisors is an integer number (532653976542).
Almost surely, 22130031211003 is an apocalyptic number.
2130031211003 is a deficient number, since it is larger than the sum of its proper divisors (584695165).
2130031211003 is an equidigital number, since it uses as much as digits as its factorization.
2130031211003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 584695164.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 2130031211003 its reverse (3001121300312), we get a palindrome (5131152511315).
The spelling of 2130031211003 in words is "two trillion, one hundred thirty billion, thirty-one million, two hundred eleven thousand, three".
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