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2130121300997 is a prime number
BaseRepresentation
bin11110111111110101000…
…111111001110000000101
321112122012211000211021102
4132333311013321300011
5234344442023112442
64310321512025445
7306616251212444
oct36776507716005
97478184024242
102130121300997
11751419a40178
122a49b9392285
13125b3c5ca031
14751540d2d5b
153a621802232
hex1eff51f9c05

2130121300997 has 2 divisors, whose sum is σ = 2130121300998. Its totient is φ = 2130121300996.

The previous prime is 2130121300981. The next prime is 2130121301003. The reversal of 2130121300997 is 7990031210312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2075071941121 + 55049359876 = 1440511^2 + 234626^2 .

It is a cyclic number.

It is not a de Polignac number, because 2130121300997 - 24 = 2130121300981 is a prime.

It is a super-2 number, since 2×21301213009972 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2130121300997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2130121306997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065060650498 + 1065060650499.

It is an arithmetic number, because the mean of its divisors is an integer number (1065060650499).

Almost surely, 22130121300997 is an apocalyptic number.

It is an amenable number.

2130121300997 is a deficient number, since it is larger than the sum of its proper divisors (1).

2130121300997 is an equidigital number, since it uses as much as digits as its factorization.

2130121300997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20412, while the sum is 38.

The spelling of 2130121300997 in words is "two trillion, one hundred thirty billion, one hundred twenty-one million, three hundred thousand, nine hundred ninety-seven".